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Happy Holidays!
Final Exam Review Sheet
2007
Exam date
Wednesday December 19th 2007 2:00-3:50
Exam format:
20 fill-in the black questions (5 from
each section --exam 1, 2, 3 and new material) 1 point
each
16 short answer questions (4
from each section) 3 points each
5 problems/longer questions (1 each from exam 1, 2 and 3 material, 2 on new stuff)
6 points each
10 multiple choice (genetic disease questions)1 point
each
Total possible points = 108
The exam will be cumulative. Approximately
15-25%
of the exam will be on new material that we have covered since the last exam. The remaining 75-85% will be on material from previous exams.
I have made a review outline for the new material and have
edited the review sheets for the old material to
exclude some topics. If you see something that was on an old
review sheet that is now missing, it means you are not responsible for that particular
material. Do try to keep in mind what are some of the bigger concepts that we
have covered during the course. Use your exams to get an idea of the type of
questions I may ask. They may be very similar or even the same.
Remember what I said way back in September about wanting students to know the answers to a
few basic questions (I posed these questions on the first day, see chapter 1) by the time
the course was over. I could very well ask those questions. One thing that I
know I will not ask you to do is solve a three point testcross. I may ask why or how
one is done, but won't ask you to solve the problem. The one type of problem I am
sure to ask is a dihybrid cross. Do remember that 15-25% of the
questions will be on the relatively small amount of material that we have covered since
exam 3, and that these questions will be more challenging. Hope this is
helpful. As usual, feel free to contact me with any questions you may have.
The old stuff:
Exam 1
Chapter 2 Mitosis and Meiosis
 | What are chromosomes? What is the difference between chromatin and
chromosomes? |
 | Be able to distinguish between chromosome, sister chromatids and
nonsister chromatids. |
 | What is a karyotype? |
 | Humans have 46 chromsomes, 23 pairs. 22 pairs of autosomes and 1 pair of
sex chromsomes. |
 | Be sure to know what a homologous pair of chromosomes
is. |
 | Review the Cell cycle. When does replication of DNA occur? |
 | Review the stages of mitosis |
 | Review the stages of meiosis. (don't worry
about sub stages of prophase 1) |
 | When does crossing over occur? |
 | What is the purpose of Meiosis?
|
 | In what cells does meiosis occur?
|
Chapter 3 Mendelian Genetics
|
|
 |
What are gametes?
|
 |
Understand the terms: monohybrid cross,
dihybrid cross, P generation, F1 generation and F2 generation.
|
 |
Know the terms homozygous or heterozygous.
|
 |
What are alleles? How many alleles does
an individual have? How many alleles does a gamete have? How many alleles can there
be in a population of organisms? |
 |
Understand the difference between dominant and
recessive traits. |
 |
Know the terms genotype and phenotype.
How do they differ? |
Monohybrid cross
This is a cross involving a single pair of
contrasting traits (monohybrid)
P (parental) PP X pp (crossing truebreeding parents)
F1 Genotype: Pp
Phenotype: purple
F2 ¼ PP + ½ Pp + ¼ pp Genotypes
¾ purple and ¼ white Phenotypes
A standard monohybrid cross results in a 1:2:1 genotypic
ratio and a 3:1 phenotypic ratio
Dihybrid cross This is a cross involving two
pairs of contrasting traits (dihybrid)
| PP = purple |
BB = short |
| Pp = purple |
Bb = short |
| pp = white |
bb = tall |
P (parental) PPBB X ppbb OR PPbb X ppBB (crossing truebreeding parents -- note that either parent shown will
result in the same F1)
F1 Genotype: PpBb
Phenotype: purple, short
F2 1/16PPBB, 2/16 PPBb, 1/16 PPbb, 2/16 PpBB, 4/16 PpBb, 2/16
Ppbb, 1/16ppBB, 2/16ppBb, 1/16 ppbb Genotypes
9/16 purple, short 3/16 purple tall 3/16 white short and 1/16 white tall Phenotypes
A dihybrid cross results in a 1:2:1:2:4:2:1:2:1 genotypic ratio and a 9:3:3:1
phenotypic ratio
 | Review the branch line diagram method of
determining F2 phenotypic and genotypic ratios. |
**Keep in mind that the above examples of monohybrid and
dihybrid crossed are by definition starting with a standard cross of truebreeding parents,
and the resulting F2 ratios will always be the same as shown above no matter what trait or
pair of traits you are considering. However it is possible to look at individual
matings of particular organisms which will not be truebreeding, and the resulting ratios
will not be the same as above. The nature of the cross would have to be specified in
some way, and the resulting phenotypes and genotypes would be calculated in a similar
manner.**
 | Review Mendel's 4 postulates and how they correlate to the presence of genes
located on homologous chromosomes and their behavior (Figure
3-11). Especially the concept of
segregation and independent assortment.
|
 | Be familiar with what a testcross is, how it is done, and what the results tell
you. Always cross to a homozygous recessive.
|
Chapter 4 Extensions of Mendelian Genetics
This whole chapter deals with situations
which alter the standard monohybrid and dihybrid phenotype ratios (3:1,
9:3:3:1). When gene expression does not adhere to a simple dominant/recessive
mode, or when more than one pair of genes influences the expression of a single character,
the classic ratios are modified. Nevertheless, the fundamental principles of
segregation and independent assortment still hold true in these situations.
 | Incomplete dominance -- the heterozygote has an intermediate
phenotype. phenotype ratio = genotype ratio in a standard monohybrid or dihybrid
cross.
Example : four o'clocks R1R1 = red, R1R2 = pink, R2R2 = white
R1R2 x R1R2 ----> 1/4 R1R1, 2/4 R1R2, 1/4 R2R2 = 1/4 red, 2/4 pink, 1/4 white |
 | Codominance --the heterozygote shows phenotype of both alleles. phenotype
ratio = genotype ratio in a standard monohybrid or dihybrid cross.
Example: MN blood groups. |
 | Multiple alleles -- For any given gene the number of alleles
within members of a population is not restricted to two. Multiple alleles = 3
or more alleles for a given gene. Any individual diploid organism has at most two
alleles of any gene.
Example: ABO Blood groups. Three alleles: IA, IB, and IO. IA, IB are
dominant to IO. IA is codominant to IB.
Table 4.1 shows the various ratios of offspring that can result from different
crosses. |
 |
Lethal alleles -- Many gene products are
essential to an organism's survival. When a mutant allele is present in may be
lethal for the individual.
 | A recessive lethal allele is lethal only if two copies of
the lethal allele are present (homozygous). Sometimes the heterozygote has a unique
phenotype (see Figure 4-4). The other normal allele
is sufficient to compensate for the mutant one. Example: AY
allele in mice, p. 85 |
 | A dominant lethal allele is lethal even when only one
copy of the allele is present. So organisms homozygous or heterozygous for the
lethal allele will die. Example: Huntington's disease |
 | With lethal alleles, the phenotype ratio is altered such that in a
standard monohybrid cross, the F2 phenotype ratio would be 2:1 instead of 3:1. The
dihybrid ratio would also be affected. |
|
 |
Be able to distinguish between the different
types of inheritance, and be able to apply these types of inheriance to new
examples. |
 |
Combinations of two gene pairs involving two
modes of inheritance modify the 9:3:3:1 ratio -- see Figure 4-5.
Be able to do this type of cross. |
 | Epistasis -- an example of gene interaction;
occurs when the expression of one gene pair masks or modifies the expression of another
gene pair. The involved genes control the expression of the same general phenotypic
trait. Has the effect of combining one or more of the four phenotypic categories of
a standard dihybrid cross in various ways. |
 | Remember, in epistasis, even though only one characteristic is
being followed (flower color for example), the phenotype ratio is expressed in 16 parts. This
is a way to see that epistasis is occurring |
 | Be familar with the inheritance of sex-linked traits |
Exam 2
Chapter 5: Linkage,
Crossing over, and Mapping
 | What is linkage? |
 | What is the difference between complete linkage and linkage with recombination? |
 | Be able to distinguish between independent assortment, linkage, and linkage with
recombination. |
 | Crossover occurs between non-sister chromatids of a
homologous pair of chromosomes. When does crossover occur?
|
 | As distance between genes on the same chromosome increase, the degree of crossing
over increases (and the number of recombinant gametes increases) |
 | Three point testcross:
 | map distance= % of all detectable exchanges occurring between 2 genes = %SCO + %DCO |
|
Chapter 7: Sex Determination and Sex
Chromosomes
 | Klinefelter and Turner syndrome
 | Be able to recognize a karyotype of these syndromes
and correctly indicate the chromosome arrangement (number of chromosomes, sex chromosomes,
deviation from normal) |
 | Both syndromes are the result of nondisjunction in meiosis |
 | What did these syndromes tell scientists about sex determination in humans? |
|
 | What is the SRY? What would happen if a female had a copy of this gene?
If a male lost this gene? |
 | Dosage compensation by X inactivation |
 | What are Barr bodies? Where are they located? How many are present in
different individuals? |
 | Mosaicism -- the Lyon hypothesis states that females are mosaics for all
heterozygous X linked alleles. |
Chapter 8: Variation in Chromosome Number and Arrangement
 | Is monosomy tolerated in plants? Animals? |
 | Downs syndrome = trisomy of chromosome 21, caused by nondisjunction |
 | Edwards syndrome = trisomy 18 |
 | Patau syndrome = trisomy 13 |
 | Polyploidy (triploid, tetraploid, etc) |
 | How is polyploidy tolerated in plants? Animals? |
 | Be able to distinguish between autoploidy and alloploidy |
 | How are tetraploids made artificially? Naturally? |
 | Be able to recognize a karyotype and correctly
indicate the chromosome arrangement (number of chromosomes, sex chromosomes, deviation
from normal) for the above disorders/conditions |
 | review the types of chromosomal rearrangements:
deletion, inversion, duplication, nonreciprocal translocation, reciprocal
translocation. |
 | What is the difference between a
paracentric inversion and a pericentric inversion? |
 | Review figures 8-21 and 8-22 |
 | Review familial down's syndrome |
Chapter 9: Extranuclear Inheritance
 | review sections 9.2, 9.3 and 9.5, and
class notes |
 | What is extranuclear
inheritance? |
 | What is maternal effect? How is
this different than maternal inheritance of mitochondrial DNA? How is it diff. than
X-linkage? |
Chapter 10: Chemical Structure
of DNA
 | DNA = the genetic
material. Several important characteristics:
 | replication |
 | storage of information |
 | expression of information |
 | variation by mutation |
|
 | Know the components of a nucleotide |
 | The four nitrogenous bases in DNA are G, A, T , and C. A and G are the
purine, C and T are the pyrimidines |
 | What type of bond links nucleotides together? |
 | Review and understand the features of the Watson
and Crick Model of DNA:
 | right handed double helix |
 | 2 strands are antiparallel (5' to 3' and 3' to 5') |
 | the bases of both chains are perpendicular to the axis of the molecule |
 | nitrogenous bases paired by hydrogen bonding (A-T; G-C) |
 | Complete turn of the helix = 34Ao |
 | 20 Ao in diameter (= pyrimmidine + purine distance) |
 | major and minor grooves |
|
 | Be able to appropriately label OR
DRAW diagram of DNA with the above features |
 | How is molecule held together by "weak" hydrogen bonds? |
 | How many hydrogen bonds between G and C? A and T? |
Chapter 11: Replication of DNA
 | Replication always occurs 5' to 3' (see Figure 11.8) |
 | DNA Polymerase requires 3' end to initiate synthesis, so requires RNA primer (see
Figure 11-11, 11-12 |
 | Leading strand synthesis is continuous, 5' to 3' |
 | Lagging strand synthesis is discontinuous, 5' to 3'. Many
points of initiation necessary because trying to replicate one way, and 5' to 3' is in the
opposite direction. |
 | Okazaki fragments --the short pieces of DNA synthesized from primers on the
lagging strand. |
 | DNA Polymerase = dimer, synthesizes both strands simultaneously |
 | FIGURE 11-13. Know
what all of the proteins illustrated are doing for the replication process and be able to
identify them in a figure:
 | helicase |
 | single stranded binding protein |
 | gyrase |
 | primase |
 | DNA Polymerase (In E. Coli, Pol III is main replication protein; Pol I is
responsible for filling in gaps left after RNA primers are removed and for
"proofreading" capabilities, Pol II repairs damage to the DNA from UV and
mutagenic chemicals) |
 | Not included in figure, but important, is DNA ligase, which joins the Okazaki
fragments after RNA primers are removed, and gaps are filled in by Pol I |
|
 | Figure 11-16, 11-17.
How does Telomerase deal with the problem of gaps at the ends of DNA? |
Exam 3
Chapter 12: DNA organization in Chromosomes
 | Review chromatin structure info on pages 292-295
and nucleosome structure |
 | What proteins are associated with DNA? What is
the nature if the interaction? |
 | review Figure 12-9 |
 | what is meant by chromosome remodeling? |
 | What does modification of histones by acetylation,
methylation or phosphorylation do?
|
Chapter 13: The
Genetic Code and Transcription
Chapter 17: Regulation of Gene Expression in Eukaryotes
 | review the characteristics of the genetic code (p.
307) |
 | review the in-class handout which summarizes studies
done to decipher the genetic code (homopolymer, mixed copolymer, repeating copolymers,
triplet binding assay) |
 | know how to determine amino acid sequence for a given
mRNA sequence. |
 | Prokaryotic Transcription See Figure 13.9
 | E. coli. RNA polymerase (a, b, b',
and s subunits) |
 | Which subunit(s) contains the active site and is responsible for the catalytic
activity of the enzyme? |
 | Which subunit is a regulatory subunit involved in recognition of the promoter? |
 | Prokaryotic promoter region includes a Pribnow box (-10) and sequences at -35 |
 | Prokaryotic transcripts are polycistronic |
 | transcription and translation simultaneous |
|
 | Eukaryotic Transcription
 | Eukaryotic transcripts are monocistronic |
 | 3 different RNA polymerases:
 | RNA Pol I -- rRNA |
 | RNA Pol II -- mRNA |
 | RNA Pol III -- tRNA, 5S RNA |
|
 | Transcription and translation are NOT simultaneous; occur in different parts of
the cell |
 | More complex regulation |
 | Processing: 5' cap, poly A tail, splicing. Where does each occur?
When? Why? |
 | RNA Pol II (2 large subunits, 10-15 smaller) |
 | What is the function of CAAT box, TATA box, enhancer? |
 | TFIID, TBP |
 | see p. 412, which summarizes differences between euk
and prok transcription |
 | Figure 17-5, eukaryotic promoter structure |
 | Figure 17-11 Assembly of transcription factors |
|
Chapter 14: Translation
 | Figure 14-1 Ribosomes consist of small and large
subunits, made up of both proteins and rRNA |
 | Figure 14-3 tRNA structure (where is anticodon
loop?/where does amino acid bind?) |
 | Charging of tRNAs. Figure 14-5
 | aminoacyl tRNA synthetase (what does this enzyme do?) |
|
 | Translation: Figures 14-6, 14-7, 14-8
 | you should be familiar with the general aspects of translation.
|
 | What is the Shine Delgarno sequence and what is its significance? |
 | What is the function of peptidyl transferase? |
|
The new stuff:
Don't forget to review the diseases for the final exam.
Don't skim new stuff--a large part of the exam will be on this
material. There will one problem from chapter 19 and one from chapter 22.
Chapter 19: Recombinant DNA Technology
 | What is recombinant DNA? |
 | Basic procedure in recombinant DNA technology involve a series of steps -- see
your notes or p. 458 |
 | Restriction enzymes
 | How are restrictions enzymes used in recombinant DNA technology? |
 | restriction enzymes recognize palindrome sequences along DNA |
 | What is a sticky end? How do they join together? |
 | What is DNA ligase used for? |
|
 | Be familiar with the plasmid vector pUC18
 | ~500 copies per cell |
 | origin of replication |
 | ampicillin resistance gene |
 | large number of restriction sites clustered in one region called polylinker |
 | lac Z gene encodes b galactosidase |
 | + X-gal = blue colonies |
 | lac Z interrupted = white colonies |
|
 | How can this vector be used to distinguish between bacterial cells that have
non-recombinant plasmid and those that have recombinant plasmid or no plasmid? |
 | Figure 19-13 overview of steps involved in cloning DNA
with a plasmid vector |
 | Polymerase chain reaction. Figure 19-17
Know the basic procedure and its applications. What
temperatures are used and why? |
 | Southern blotting. Figure 19-24. Know the
basic procedure and its applications |
 | Sequencing: FIGURE 19-26, 19-27 Know the procedure,
how to "read" a gel and its applications.
|
Chapter 22: Applications and Ethics of Genetic Technology
 | How is amniocentesis done, and what kind of
analysis can be done with samples obtained? |
 | How can an individual with thalassemia
or sickle cell anemia be identified by recombinant DNA techniques? What are
the steps involved in this procedure? (see Figure 22-9) |
 | What are ASOs? How
can they be used for genetic testing? Be able to analyze results of
these types of experiments (see figures 22-10. 22-11 ) |
 |
What are microarrays?
What can they be used for? |
 | What are RFLPs?
How can they be used for gene mapping? (linkage analysis) |
 | What is FISH? How
is it done? |
There will none of Chapter 18 on the exam.
Chapter 18: Genetics of Cancer--ONLY
WHAT WE GET TO IN CLASS
Much of the material we spoke about on cancer was not from the book, but from
the two cancer lab handout introductions, and my own other sources, so definitely refer to
your notes.
 | Normal cells:
 | have defined lifespan in culture. They will grow for a while, undergo
"crisis" and then die |
 | contact inhibited -- cell growth ceases under conditions of decreased nutrients,
injury, or cell division, or if space is physically limiting (crowding on plate) |
 | cells adhere to tissue culture plate and to one another
|
|
 | Cancer cells have distinguishing characteristics:
 | immortal |
 | loss of contact inhibition - cells overgrow, pile on top of one another |
 | anchorage independent -- cancer cells are less adherent to each other and the
tissue culture plate |
 | morphological changes |
 | chromosomal aberrations |
|
 | All types of cancer have a common distinguishing feature:
LOSS OF GROWTH CONTROL |
 | Proto-oncogenes
 | normal genes, encode normal proteins involved in accelerating growth of the cell |
 | if mutated, become oncogenes |
|
 | Tumor suppressors
 | normal function--restrict cellular proliferation |
 | if mutated or inactivated, cellular proliferation without regulation |
 | Review information on p53 -- what type of protein is it? What is its normal
function? what does it interact with? How does it restrict cell growth? |
 | Review information on pRB --what type of protein is it? What is its normal
function? what does it interact with? How does it restrict cell growth? |
|
 | Somatic mutations vs. Germline mutations |
 | mutations include nucleotide changes, chromosomal rearrangements, chromosome loss |
 | Cancer cells -- to key events cause change to cancerous cell
 | uncontrolled growth |
 | ability to metastasize |
|
 | Cell cycle -- G1/S and G2/M transitions regulated (see text, ch. 23, pp. 635-638) by two classes of proteins:
 | protein kinases (ex. CDK1) |
 | cyclins (ex. cyclin B) |
|
 | G2/M transition regulated by cyclinB/CDK1 complex (Figure 23.3) |
 | Retinoblastoma
 | familial vs. sporadic (See Figure 23.4) |
 | symptoms |
|
 | Tumor suppressors:pRB
 | How is it regulated? (See figure 23.5) When is it
active/inactive? How does this occur? |
|
 | Tumor suppressor: p53
 | mutations in p53 gene are most common |
 | normally low levels increase in response to DNA damage |
 | 2 responses: arrest cell cycle (How? Know the p21 story) and
initiate apoptosis |
|
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